Love For MathCreative Math Education

DIY Challenge 3: Eight cards, three groups

If you had only 8 cards (Ace to 8), how many ways would be there to divide them into 3 groups of total equal value?

What students worked out7

  • Student 10

    Sum cards from 1 to 8 = 36.
    So, if we are to divide these cards in equal groups of 3, each group of cards should have the sum 13

  • Student 4

    Student 10 is incorrect sir. 36/3 is not 13, since 13*3 is 39. The right answer is 12. 12 should be the sum of the cards in every group.

    • Student 2

      i agree

  • Student 1

    1 plus numbers to 8=36 36/3=12 so therefore groups will have the sum of 12 in each group.

  • Student 3

    only 2 ways we can divide 1 to 8 in 3 piles

    1236
    48
    57

    and

    138
    246
    57

    i think so

  • Student 6

    total is 12
    1236,48,75

  • Student 5

    There are only 2 ways. I think so
    1236
    48
    57
    and
    138
    246
    57