DIY Challenge 1
What students worked out21
Student 21
4
Karanteacher
Which are the 4 ways? Can you try to find more.
Student 4
16 ways
GBRO
GRBO
GORB
GOBR
In this manner, each ball will have this patternStudent 4
So 4×4=16
Student 11
6
Student 11
Sorry there are 12
Student 2
12 ways
Student 4
Actually 12 ways because if we start with red or blue then we have only one way for those, so we lose 4 ways
Student 14
1)ORBG
2)OBRG
3)GRBO
4)GBROStudent 14
5)GOBR
6)OGRB
7)GORB
8)OGBRStudent 14
9)RBGO
10)BRGO
11)RBOG
12)BROG
Student 14
1)ORBG
2)OBRG
3)GRBOStudent 1
i think there are 12 ways
Student 21
it 6
Student 21
its 12
BRGO
BROG
RBOG
RBGO
GBRO
OBRG
GRBO
ORBG
OGBR
GOBR
OGRB
GORBStudent 21
advik’s answer is
its 12
GRBO
GBRO
GORB
RBOG
RBGO
BRGO
BROG
OBRG
ORBG
OGRB
GOBR
OGBRStudent 9
If we assume RB = BR, then the answer will be
1)RBOG
2)RBGO
3)GRBO
4)ORBG
5)OGRB
6)GORB
Or else the answer will be
1)RBOG
2)RBGO
3)GRBO
4)ORBG
5)OGRB
6)GORB
7)BROG
8)BRGO
9)GBRO
10)OBRG
11)OGBR
12)GOBRStudent 2
12
Student 15
So, sir, we have to stick red and blue together so we can assume them as 1 ball and so we can calculate the answer for 3, but if we change the position from rb to br it has the same value so we can multiply the number of balls for three into 2 as it is getting repeated because of the change in the positioning of red blue to blue red.
Student 3
12 ways
6 ways as RB and 6 ways as BRStudent 17
I got 12 ways,6 blue then red and 6 red then blue