Love For MathCreative Math Education

Challenge 3: Dividing consecutive terms

Here is a new experiment to try out. Here is the Fibonacci series.

1, 1, 2, 3, 5, 8, 13, 21, 34, 55, …..

Divide 2 consecutive terms of the Fibonacci series. For example:

The 1st and 2nd terms: 1/1 = 1
The 2nd and 3rd terms: 2/1 = 2
The 3rd and 4th terms: 3/2 = 1.5
………..

Do it for at least 5 more terms. Do you observe any pattern or anything interesting?

What students worked out5

  • Student 1

    1/1 = 1
    2/1 = 2
    3/2 = 1.5
    5/3 = 1.666666 (recurring)
    8/5 = 1.6
    13/8 = 1.625
    21/13 = 1.615384 (recurring)
    34/21= 1.619047 (recurring)

  • Student 1

    It is always close to 1.6 except the first 3 calculations.

    • Student 3

      i agree with Student 1

  • Student 8

    1.7

  • Student 4

    Sir, I agree with Student 1