Challenge 3: Dividing consecutive terms
Here is a new experiment to try out. Here is the Fibonacci series.
1, 1, 2, 3, 5, 8, 13, 21, 34, 55, …..
Divide 2 consecutive terms of the Fibonacci series. For example:
The 1st and 2nd terms: 1/1 = 1
The 2nd and 3rd terms: 2/1 = 2
The 3rd and 4th terms: 3/2 = 1.5
………..
Do it for at least 5 more terms. Do you observe any pattern or anything interesting?
What students worked out5
Student 1
1/1 = 1
2/1 = 2
3/2 = 1.5
5/3 = 1.666666 (recurring)
8/5 = 1.6
13/8 = 1.625
21/13 = 1.615384 (recurring)
34/21= 1.619047 (recurring)Student 1
It is always close to 1.6 except the first 3 calculations.
Student 3
i agree with Student 1
Student 8
1.7
Student 4
Sir, I agree with Student 1